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dc.contributor.authorHyde, James
dc.contributor.authorJonusas, Julius
dc.contributor.authorMitchell, J. D.
dc.contributor.authorPeresse, Y. H.
dc.date.accessioned2016-12-07T16:51:40Z
dc.date.available2016-12-07T16:51:40Z
dc.date.issued2016-05-13
dc.identifier.citationHyde , J , Jonusas , J , Mitchell , J D & Peresse , Y H 2016 , ' Universal sequences for the order-automorphisms of the rationals ' , Journal of the London Mathematical Society . https://doi.org/10.1112/jlms/jdw015
dc.identifier.issn1469-7750
dc.identifier.otherArXiv: http://arxiv.org/abs/1401.7823v4
dc.identifier.urihttp://hdl.handle.net/2299/17397
dc.descriptionThis is the accepted version of the following article: J. Hyde, J. Jonušas, J. D. Mitchell, and Y. Péresse, Universal sequences for the order-automorphisms of the rationals, J. London Math. Soc., first published online May 13, 2016 which has been published in final form at doi:10.1112/jlms/jdw015
dc.description.abstractIn this paper, we consider the group Aut$(\mathbb{Q}, \leq)$ of order-automorphisms of the rational numbers, proving a result analogous to a theorem of Galvin's for the symmetric group. In an announcement, Kh\'elif states that every countable subset of Aut$(\mathbb{Q}, \leq)$ is contained in an $N$-generated subgroup of Aut$(\mathbb{Q}, \leq)$ for some fixed $N\in\mathbb{N}$. We show that the least such $N$ is $2$. Moreover, for every countable subset of Aut$(\mathbb{Q}, \leq)$, we show that every element can be given as a prescribed product of two generators without using their inverses. More precisely, suppose that $a$ and $b$ freely generate the free semigroup $\{a,b\}^+$ consisting of the non-empty words over $a$ and $b$. Then we show that there exists a sequence of words $w_1, w_2,\ldots$ over $\{a,b\}$ such that for every sequence $f_1, f_2, \ldots\in\,$Aut$(\mathbb{Q}, \leq)$ there is a homomorphism $\phi:\{a,b\}^{+}\to$ Aut$(\mathbb{Q},\leq)$ where $(w_i)\phi=f_i$ for every $i$. As a corollary to the main theorem in this paper, we obtain a result of Droste and Holland showing that the strong cofinality of Aut$(\mathbb{Q}, \leq)$ is uncountable, or equivalently that Aut$(\mathbb{Q}, \leq)$ has uncountable cofinality and Bergman's property.en
dc.format.extent210161
dc.language.isoeng
dc.relation.ispartofJournal of the London Mathematical Society
dc.subjectGroup Theory
dc.subjectInfinite Combinatorics
dc.titleUniversal sequences for the order-automorphisms of the rationalsen
dc.contributor.institutionSchool of Physics, Astronomy and Mathematics
dc.description.statusPeer reviewed
dc.identifier.urlhttp://arxiv.org/pdf/1401.7823v4.pdf
rioxxterms.versionofrecord10.1112/jlms/jdw015
rioxxterms.typeJournal Article/Review
herts.preservation.rarelyaccessedtrue


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